While solving Problems Involving Age, we consider the age to be found as x. If in the statement it is mentioned after certain years then that value is added in the age of all the people. Similarly if it is mentioned before or ago certain years then that value is subtracted from the age of all the people.
Illustration: Reena is four years older than Rohan. Five years ago, Reena's age was five times Rohan's age. Find the ages of Reena and Rohan.
Solution Let Rohan's age be x years. Then, Reena's age is (x+4)years.
Six years ago, Rohan's age was (x-5) years.
Reena's age was (x+4-5) years = (x-1) years.
It is given that five years ago Reena's age was five times Rohan's age.
Hence, Rohan's age = 6 years
Reena's age = (x+4) years = (6+4) years = 10 years.
The sum of ages of a son and his father is 35 years and the product of their ages is 150. Find their present ages | |||
Right Option : B | |||
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The age of a man is same as his wife's age with the digits reversed. Then sum of their ages is 99 years and the man is 9 years older than his wife. The age of man and his wife is | |||
Right Option : B | |||
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The age of a father is equal to the square of the age of his son. The sum of the age of the father and five times the age of the son is 66 years. Find their present ages. | |||
Right Option : A | |||
View Explanation |
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